Oracle 1Z0-007 Exam - PassITexam.com

Free 1Z0-007 Sample Questions:

1. What does the FORCE option for creating a view do?
A.creates a view with constraints
B.creates a view even if the underlying parent table has constraints
C.creates a view in another schema even if you don't have privileges
D.creates a view regardless of whether or not the base tables exist
Answer: D

2. What are two reasons to create synonyms? (Choose two.)
A.You have too many tables.
B.Your tables are too long.
C.Your tables have difficult names.
D.You want to work on your own tables.
E.You want to use another schema's tables.
F.You have too many columns in your tables.
Answer: C, E

3. The STUDENT_GRADES table has these columns: STUDENT_ID NUMBER(12)
SEMESTER_END DATE GPA NUMBER(4,3)
The registrar requested a report listing the students' grade point averages (GPA) sorted from highest grade point average to lowest.
Which statement produces a report that displays the student ID and GPA in the sorted order requested by the registrar?
A.SELECT student_id, gpa FROM student_grades ORDER BY gpa ASC;
B.SELECT student_id, gpa FROM student_grades
SORT ORDER BY gpa ASC;
C.SELECT student_id, gpa
FROM student_grades
SORT ORDER BY gpa;
D.SELECT student_id, gpa FROM student_grades ORDER BY gpa;
E.SELECT student_id, gpa FROM student_grades
SORT ORDER BY gpa DESC;
F.SELECT student_id, gpa FROM student_grades
ORDER BY gpa DESC;
Answer: F

4. In which three cases would you use the USING clause? (Choose three.)
A.You want to create a nonequijoin.
B.The tables to be joined have multiple NULL columns.
C.The tables to be joined have columns of the same name and different data types.
D.The tables to be joined have columns with the same name and compatible data types.
E.You want to use a NATURAL join, but you want to restrict the number of columns in the join condition.
Answer: C, D, E

5. The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20)
The CUSTOMER_ID column is the primary key for the table.
You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?
A.COUNT(UPPER(country_address))
B.COUNT(DIFF(UPPER(country_address)))
C.COUNT(UNIQUE(UPPER(country_address)))
D.COUNT DISTINCT UPPER(country_address) E.COUNT(DISTINCT (UPPER(country_address)))
Answer: E

6. Click the Exhibit button and examine the data in the EMPLOYEES table.

Which three subqueries work? (Choose three.)
A.SELECT *
FROM employees
where salary > (SELECT MIN(salary) FROM employees
GROUP BY department_id);
B.SELECT *
FROM employees
WHERE salary = (SELECT AVG(salary) FROM employees
GROUP BY department_id);
C.SELECT distinct department_id FROM employees
WHERE salary > ANY (SELECT AVG(salary) FROM employees
GROUP BY department_id);
D.SELECT department_id
FROM employees
WHERE salary > ALL (SELECT AVG(salary) FROM employees
GROUP BY department_id);
E.SELECT last_name
FROM employees
WHERE salary > ANY (SELECT MAX(salary) FROM employees
GROUP BY department_id);
F.SELECT department_id FROM employees
WHERE salary > ALL (SELECT AVG(salary) FROM employees
GROUP BY AVG(SALARY));
Answer: C, D, E

7. A SELECT statement can be used to perform these three functions:
1. Choose rows from a table.
2. Choose columns from a table.
3. Bring together data that is stored in different tables by creating a link between them. Which set of keywords describes these capabilities?
A.difference, projection, join
B.selection, projection, join
C.selection, intersection, join
D.intersection, projection, join
E.difference, projection, product
Answer: B

8. Evaluate this SQL statement:
SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME
FROM EMPLOYEES e, DEPARTMENTS d
WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID;
In the statement, which capabilities of a SELECT statement are performed?
A.selection, projection, join
B.difference, projection, join
C.selection, intersection, join
D.intersection, projection, join
E.difference, projection, product
Answer: A

9. Evaluate this SQL statement:
SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct)
+ (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s
WHERE e.employee_id = s.emp_id;
What will happen if you remove all the parentheses from the calculation?
A.The value displayed in the CALC_VALUE column will be lower.
B.The value displayed in the CALC_VALUE column will be higher.
C.There will be no difference in the value displayed in the CALC_VALUE column.
D.An error will be reported.
Answer: C

10. Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?
A.SELECT ename, salary*12 'Annual Salary' FROM employees;
B.SELECT ename, salary*12 "Annual Salary" FROM employees;
C.SELECT ename, salary*12 AS Annual Salary FROM employees;
D.SELECT ename, salary*12 AS INITCAP("ANNUAL SALARY") FROM employees
Answer: B

11. Evaluate this SQL statement: SELECT ename, sal, 12*sal+100 FROM emp;
The SAL column stores the monthly salary of the employee. Which change must be made to the above syntax to calculate the annual compensation as "monthly salary plus a monthly bonus of $100, multiplied by 12"?
A.No change is required to achieve the desired results.
B.SELECT ename, sal, 12*(sal+100) FROM emp;
C.SELECT ename, sal, (12*sal)+100 FROM emp;
D.SELECT ename, sal+100,*12 FROM emp;
Answer: B

12. The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL CUSTOMER_ADDRESS VARCHAR2(150) CUSTOMER_PHONE VARCHAR2(20)
You need to produce output that states "Dear Customer customer_name, ".
The customer_name data values come from the CUSTOMER_NAME column in the CUSTOMERS table. Which statement produces this output?
A.SELECT dear customer, customer_name,
B.SELECT "Dear Customer", customer_name || ',' FROM customers;
C.SELECT 'Dear Customer ' || customer_name ',' FROM customers;
D.SELECT 'Dear Customer ' || customer_name || ',' FROM customers;
E.SELECT "Dear Customer " || customer_name || ","FROM customers;
F.SELECT 'Dear Customer ' || customer_name || ',' || FROM customers;
Answer: D

13. Which two are attributes of iSQL*Plus? (Choose two.)
A.iSQL*Plus commands cannot be abbreviated.
B.iSQL*Plus commands are accessed from a browser.
C.iSQL*Plus commands are used to manipulate data in tables.
D.iSQL*Plus commands manipulate table definitions in the database.
E.iSQL*Plus is the Oracle proprietary interface for executing SQL statements.
Answer: B, E

14. Which is an iSQL*Plus command?
A.INSERT
B.UPDATE
C.SELECT
D.DESCRIBE
E.DELETE
F.RENAME
Answer: D

15. Which are iSQL*Plus commands? (Choose all that apply.)
A.INSERT
B.UPDATE
C.SELECT
D.DESCRIBE
E.DELETE
F.RENAME
Answer: D